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(3%) Problem 9: Consider the circuit diagram in the figure. Ez= 18 V d. 0.5 0 2.5 0 R, 6.0 2 R, 1.52 0.5 0 E, = 45 V ©theexpertta.com E V 50% Part

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(a) What is the equation which results when applying the loop rule to loop aedcba, in terms of the variables given in the figure? 0 = ( 12 R2 ) – 61 + ( I2 r¡ ) + ( I1 R1 ) Correct! D * 50% Part (b) What is the current through the top loop I2, in amps? Grade Summary Deductions 8% Potential 92% sin() 9 HOME cos() tan() Submissions asin() acos() 4 cotan() Attempts remaining: 3 (4% per attempt) detailed view 1 2 3 atan() cosh() oDegrees acotan() sinh() cotanh() tanh() END 4% Vol BACKSPACE Radians |CLEAR 4% I give up! Submit Feedback Hint for a 0% deduction. Hints remaining: 0 Feedback: 2% deduction per feedback. Hints: |-What other expressions, besides what you’ve entered in (a), apply to this circuit? -There are three equations which come from applying Kirchhoff’s laws, and

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